Find the equation of the straight line joining to the origin to the point of intersection of x2 + y2 -4x-2y=0 and x2 +y2 -2x-4y=4

Dear student,
I am assuming your query was 
Find the equation of the straight line joining origin to the point of intersection of x² + y² -4x-2y=0 and x² +y² -2x-4y=4​​​.
If that is so then the solution is as follows
Step 1:-Find the point of intersection Subtract the equation of the two circles
-4x-2y+2x+4y=0-4
-2x+2y=-4
x-y=2​​​
x=2+y
Substituting in the circle equation we have 
(2+y)²+y²-4(2+y)-2y=0
y²+4+4y+y²-8-4y-2y=0
2y²-2y-4=0
y²-y-2=0
(y-2)(y+1)=0
y=2,-1
x=4,1
Hence the points are (4,2) and (1,-1)
Step 2:-Equation of any line passing through origin is y=mx
(4,2) satisfies
2=4m
m=1/2
equation y=x/2
(1,-1) satisfies
-1=m
m=-1
equation is y=-x
Hence the equations are y=x/2 and y=-x
Hope that helps
Regards.​