Find the equation of the straight line passing through the point of intersection of the two lines x+2y+3=0and3x+4y+7=0 and parallel to the straight line y-x=8 Share with your friends Share 1 Neha Sethi answered this Dear student x+2y+3=0 ...13x+4y+7=0 ...2 On solving the above equations we getx=-1 and y=-1Point of intersection of x+ 2y+3=0 and is -1,-1The equation of line parallel to the straight line y-x-8=0 is y-x+k=0-1+1+k=0⇒k=0∴the required equation of the straight line is y-x=0 Regards 2 View Full Answer