Find the equation of the straight line passing through the point of intersection of the two lines x+2y+3=0and3x+4y+7=0 and parallel to the straight line y-x=8

Dear student
x+2y+3=0      ...13x+4y+7=0    ...2  On solving the above equations  we getx=-1 and y=-1Point of intersection  of x+ 2y+3=0 and   is -1,-1The equation of line parallel to  the straight line y-x-8=0 is y-x+k=0-1+1+k=0k=0the required equation  of the straight line is y-x=0

Regards
 

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