find the extreme values of cosx* cox(2pi/3 + x) *cos(2pi/3 - x) Share with your friends Share 13 Mayur Pisode answered this cos x . cos 2π3+x2π3-x=cos x cos22π3 - sin2x=cos xcos2π-π3 - sin2x= cos x cos2π3 - sin2x=cos x 14 - 1 - cos2x=cos x -34 + cos2x=144 cos3x - 3 cos x=14 cos 3xNow, we know that minimum value of cos 3x is -1So, minimum value of 14 cos 3x = -14Now, maximum value of cos 3x is 1So, maximum value of 14 cos 3x = 14 37 View Full Answer
