Find the general solution: 1) sin 9 theta= sin theta Share with your friends Share 7 Varun Rawat answered this We have, sin 9θ = sin θ⇒sin 9θ - sin θ = 0⇒2 cos9θ + θ2 . sin9θ - θ2 = 0⇒cos 5θ . sin 4θ = 0⇒cos 5θ = 0 or sin 4θ = 0⇒5θ = 2m+1π2 or 4θ = nπ⇒θ = 2m+1π10 or θ = nπ4 ; where m, n∈I 18 View Full Answer
