Find the largest number that divides 2053 & 967 and leaves a remainder of 5 and 7.

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Onkar Mathekar answered this

The largest number is = HCF(2048,960) =64

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Rahulsiddharth answered this

2053-5=2048

967-7=960

2048=2x2x2x2x2x2x2x2x2x2x2

960=2x2x2x2x2x2x3x5

HCF OF 2048960=2⁶=64

therefore,the largest number that divides 2053 967 and leaves a remainder of 5 and 7 is 64

Pradeep S answered this

hcf{2053-5,967-7} = 64

P Hritik Rao Rockzz answered this

waaat??

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P Hritik Rao Rockzz answered this

053 and 967 and leaves a remainder of 5 and 7 is 64

-7

Pihu Rajput answered this

Please find this answer

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Pihu Rajput answered this

Please find this answer

Aryan Sankhla answered this

It is given that on dividing 2053 by the required number there is a remainder of 5 .this mean that 2053 - 5 = 2048 is exactly divisible by required number . similarly,
967 - 7 = 960
the required number is the largest number satisfying the above property .
therefore ,it is the HCF of 2048 & 960
HCF of 2048 & 960 is 64
hence required number is 64

Samson answered this

Madhavan answered this

The answer is 64

Vidhita answered this

Subtract both numbers by 5 and 7

Ak. B answered this

See, largest number = HCF. So find HCF of 2048 and 960( because 2053-5 and 967-7)

Qwerty answered this

Answer

Ananya Gupta answered this

Hope u understand it.....

Godly Seol answered this

4564

Abhishek answered this

2053-5=2048

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Aman Narwal answered this

64 is the answer

Sannidhya Mate answered this

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Ganesh answered this

Ans=64

Dhappi Rana answered this

7353

Silent Killer answered this

3546

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Ashmita Suryavanshi answered this

HCF = [2048,960] = 64

Ashmita Suryavanshi answered this

Shivam056 Kumar answered this

Hi,. Here is answer.

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Sannidhya Mate answered this

64 thanx

Kush answered this

Vikas Yadav answered this

hiii it was too easy

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Vikas Yadav answered this

bhai nhi aata

Pranjal Sahu answered this

the largest number is 64
2048=2¹¹
960=2⁶*3*5
HCF=2⁶=64

Jyoti Bhatia answered this

Largest number=64

Prajwal Poddar answered this

2053-5=2048

967-7=960

2048=2x2x2x2x2x2x2x2x2x2x2

960=2x2x2x2x2x2x3x5

HCF OF 2048960=26=64

therefore,the largest number that divides 2053 967 and leaves a remainder of 5 and 7 is?64

Here u go
Cheers

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Tanu Verma answered this

643

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Tanu Verma answered this

sry its 64

Komal Saini answered this

Please find this answer

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Kanchan answered this

738377372727

-2

Bhawna💖💎 answered this

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Sreeyanthrao answered this

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Khushi Dhoot answered this

2053-5=2048

967-7=960

2048=2x2x2x2x2x2x2x2x2x2x2

960=2x2x2x2x2x2x3x5

HCF OF 2048960=26=64

therefore,the largest number that divides 2053 967 and leaves a remainder of 5 and 7 is?64

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Sukhidharan Km answered this

hcf =64

Saurav answered this

64 Is the answer

-1

Ashish Singh answered this

Ne sais pas

Ashish Singh answered this

1234

Ashish Singh answered this

Abcde

Ashish Singh answered this

Hey Mate,

2053-5=2048

967-7=960

2048=2x2x2x2x2x2x2x2x2x2x2

960=2x2x2x2x2x2x3x5

HCF OF 2048960=26=64

Therefore,the largest number that divides 2053 967 and leaves a remainder of 5 and 7 is?64.

Cheers !

Miya answered this

It is given that 2053 leaves 5 as the remainder. Therefore,2053-5=2048 Similarly, 967 leaves 7 as the remainder. Therefore,967-7=960 Now, HCF(960,2048)=64 Hence,64 is the greatest number which when divides 2053 and 967 leaves a remainder of 5 and 7 resp.

Hemant answered this

64 leaves the remainder 5 and 7 for 2053 and 967, respectively.

Simran Soni answered this

Please find this answer

Rudraksh Sharma answered this

64 IS THE HCF

Suman Dash answered this

2053-5= 2048
967-7 = 960
hence the numbers are (2048, 960)
2048=2 x 2 x 2 x 2 x 2 x 2x 2 x 2 x 2 x 2 x 2
960 =2 x 2 x 2 x 2x 2 x 2 x 3 x 5
hcf( 2053 960) 64

Hrishikesh Deshpande answered this

The answer is 64

Anjali Hansda answered this

hope this is correct....

Shivraj Barsole answered this

64 is the number

Soumya Ranjan Bhatta answered this

math

Sadiya Maheen Siddiqui answered this

2053-5=2048

967-7=960

2048=2x2x2x2x2x2x2x2x2x2x2

960=2x2x2x2x2x2x3x5

HCF OF 2048960=26=64

Therefore, the largest number that divides 2053 967 and leaves a remainder of 5 and 7 is 64.

Veer Gajjar answered this

The correct answer is 64

𝓡𝓸𝓱𝓲𝓽 answered this

Hogi

Mushraf answered this

what is mean by the Redox reaction

Jyoti answered this

10 + 10

Anshu Kumari answered this

2053-5=2048

967-7=960

2048=2x2x2x2x2x2x2x2x2x2x2

960=2x2x2x2x2x2x3x5

HCF OF 2048960=26=64

therefore,the largest number that divides 2053 967 and leaves a remainder of 5 and 7 is?64

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𝓡𝓸𝓱𝓲𝓽 answered this

Yeah book

Ayush Thapliyal answered this

64 ans

Saloni answered this

Ans-64

Sahasra Bharadwaj answered this

64 is the answer.

Sahasra Bharadwaj answered this

ANS = 64

Tanvi Chavda answered this

hcf = 64

Anshika Saini answered this

Mathematics Chapter I Real numbers Excrise 1.2

Neha Thomas answered this

The largest number is = HCF(2048,960) =64

Neha Thomas answered this

hope this helps you .

Neha Thomas answered this

hope you got the required answer .

Tejaswini J answered this

2053-5=2048

967-7=960

2048=2x2x2x2x2x2x2x2x2x2x2

960=2x2x2x2x2x2x3x5

HCF OF 2048960=2⁶=64

therefore,the largest number that divides 2053 967 and leaves a remainder of 5 and 7 is 64

Sushree Swayamsmita answered this

Hence, number N is 64 which will give remainders 5 and 7 on dividing 2053 and 967 respectively.

Aaryansh Tilak answered this

ANSWER IS
64

Vatsar Sharda answered this

2053−5=2048
967−7=960

Prime factors of 2048=2×2×2×2×2×2×2×2×2×2
Prime factors of 960=2×2×2×2×2×2×3×5
HCF of 2048 and 960=2×2×2×2×2×2=64

Goushia Shahnawaz answered this

2053-5=2048
967-7=960
Required no=LCM of (2048,960)
=16

Find the largest number that divides 2053 & 967 and leaves a remainder of 5 and 7.

2053−5=2048 967−7=960

2053−5=2048
967−7=960