Find the least number which should be added to 2497 so that sum is exactly divisible by 5; 6; 4; 3

Dear Student,



L.C.M. of 5, 6, 4 and 3 = 2×2×3×5 = 60On dividing 2497 by 60, the remainder is 37Now, we divide 2497 by 60, 



On dividing 2497 by 60, the remainder is 37Number to be added = 60-37 = 23Hence, 23 must be added to 2497 so that 2497+23 = 2520 is exactly divisible by 5, 6, 4 and 3

Regards

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