Find the least number which when divided by 12, 16 and 36 leaves a remainder 7 in each case?
Dear Student
Solve your question in similar way.
First we have to find the L.C.M of 12,16,24,36
L.C.M by prime factorization method
12= 2*2*3
16=2*2*2*2
24= 2*2*2*3
36= 2*2*3*3
L.C.M= 2*2*2*2*3*3 = 144
Add remainder 7 to the L.C.M = 144+7= 151
The least number which when divided by 12,16,24 and 36 leaves a remainder 7 in each case IS 151
Regards
Solve your question in similar way.
First we have to find the L.C.M of 12,16,24,36
L.C.M by prime factorization method
12= 2*2*3
16=2*2*2*2
24= 2*2*2*3
36= 2*2*3*3
L.C.M= 2*2*2*2*3*3 = 144
Add remainder 7 to the L.C.M = 144+7= 151
The least number which when divided by 12,16,24 and 36 leaves a remainder 7 in each case IS 151
Regards