Find the limit of sin7x / tan3x as x tends to zero. plz answer soon...

limx0sin7xtan3xSo limx0sin7xsin3xcos3x=limx0sin7x×cos3xsin3xMultiply and divide the numerator by 7x and multiply and divide the denominator by 3x.Solimx0sin7x×cos3xsin3x = limx0sin7x7x×7x×cos3xsin3x3x×3xAs limx0sinxx=1, so limx0sin3x3x=1, limx0sin7x7x=1Hence limx0sin7x7x×7x×cos3xsin3x3x×3x =limx01×7x×cos3x1×3xAs limx0cosx =1, so limx0cos3x =1Hence limx01×7x×cos3x1×3x =7x3x=73So limx0sin7xtan3x=73 (Ans)

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limx=0sin7x = 7x

limx=0tan3x = 3x

the4 limx=0sin7x/tan3x =7x/3x =7/3

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