FIND THE MODULUS OF (1+7i) / (2-i)2

The given complex number is, 1+7i2-i2=1+7i4+i2-4i=1+7i4-1-4i=1+7i3-4i As we know that i2=-1Now rationalising the denominator we get, =1+7i3-4i×3+4i3+4i=3+21i+4i+28i232-4i2=3-28+25i9-16i2=-25+25i9+16=-25+25i25=-1+iNow modulus of -1+i = -12+12=2

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