Find the.modulus of 1+cos theta+i sin theta/1+cos theta-isin theta

Hi,

  • 1
Hello Mrunal, |z1/z2| = |z1| / |z2|
Let us find modulus of numerator
| 1 + cos @ + i sin @| = ​√{(1+cos @)^2 + sin^2 @}
For denominator
| 1 + cos @ - i sin @| = √{(1+cos @)^2 + sin^2 @}
Since both are one and the same their ratio is 1
Hence mod of given = 1

 
  • -2
What are you looking for?