Hello Mrunal, |z1/z2| = |z1| / |z2|

Let us find modulus of numerator

| 1 + cos @ + i sin @| = √{(1+cos @)^2 + sin^2 @}

For denominator

| 1 + cos @ - i sin @| = √{(1+cos @)^2 + sin^2 @}

Since both are one and the same their ratio is **1**

Hence mod of given = 1