Hello Mrunal, |z1/z2| = |z1| / |z2|
Let us find modulus of numerator
| 1 + cos @ + i sin @| = √{(1+cos @)^2 + sin^2 @}
For denominator
| 1 + cos @ - i sin @| = √{(1+cos @)^2 + sin^2 @}
Since both are one and the same their ratio is 1
Hence mod of given = 1
