Find the modulus of i^25 +(1+3i)^3.
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=(i^24 × i) + (1+3i)^3 =i + 1 + 27i^3 + 9i + 27i^2 [since (a+b)^3=a^3+b^3+3a^2b+3ab^3] =i +1 - 27i + 9i - 27 =- 26 -17i X=-26, y=-17 Modulus of (-26 -17i)=√(-26)^2+ (-17)^2 =√965