find the moment of inertia about an axis AA which passes through the centre of mass of two particles m1 and m2 at a distance r from each other.

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Let the centre of mass is at position R from mass m1 then R=m1×0+m2×rm1+m2=m2×rm1+m2and distance of centre of mass from m2 will be =r-R=r-m2×rm1+m2=m1×rm1+m2So the moment of inertia of the system I=m1m2×rm1+m22+m2m1×rm1+m22I=r2m1m22+m12m2m1+m22I=m1m2m1+m2r2

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