find the net force Share with your friends Share 0 Neha Gupta answered this When the loop is placed with the longest side parallel to the long straight wire, thenthe shortest sides of the loop at the same distance from the wire and force on them are equal but in opposite direction therefore net force on two short sides are zero.Now longest side which near the wire, force on it is given by:F1 = B1IloopLwhere B is the magnetic field due to wire L is the length of the side of the loop.B = μ0I2πrwhere r is the distance of the sideo of the loop.let direction of the current in wiire is in upward direction.F1 = μ0IwireIloopL2πrF1 = 4π×10-7×25×15×252π×2F1 = 9.37×10-4 N away from the wireforce on the longest side which is away frm the wire F2 = μ0IwireIloopL2π(r+length ofthe shortest side)F2 = 4π×10-7×25×15×252π×12F2 = 1.56×10-4N towards the wirenet force F = F1-F2 = 7.81 ×10-4 N away from the wire 16 View Full Answer
