# Find the number of air molecules in a room of volume 12mcube. Given one mole of air at NTP occupies a volume of 22.4liters

Dear Student,

Please find below the solution to the asked query:

Given that the gas volume is $V=12{m}^{3}=12000l$

So, the volume of one mole of gas is *22.4 l*. Therefore,

Number of moles in gas is,

$n=\frac{12000}{22.4}=535.7mol$

As we know, one mol of gas will have avagadro number of molecules. Therefore, the total number of molecules are,

$N=nA=535.7\times 6.02\times {10}^{23}=3.25\times {10}^{26}$

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