find the number of atoms of each type present in 3.42grams of cane sugar ( C 12 H22O11)
Molar mass of C12H22O11 = 342 g/mol
1 mole of C12H22O11 = 342 g
3.42 g of C12H22O11 = 0.01 mole of C12H22O11.
Mass of C in 342 g C12H22O11 = 12 x 12 = 144 g
Mass of C in 3.42 g of C12H22O11 = 1.44 g
Mass of H in 342 g C12H22O11 = 22 x 1 = 22 g
Mass of H in 3.42 g of C12H22O11 = 0.22 g
Mass of O in 342 g C12H22O11 = 11 x 16 = 176 g
Mass of O in 3.42 g of C12H22O11 = 1.76 g
Number of atoms = number of moles x 6.023 x 1023 atoms
Number of C atoms=
Number of H atoms=
Number of O atoms=