find the number of atoms of each type present in 3.42grams of cane sugar ( C 12 H22O11)

Molar mass of C12H22O11 = 342 g/mol

1 mole of C12H22O11 = 342 g

3.42 g of C12H22O11 = 0.01 mole of C12H22O11.

Mass of C in 342 g C12H22O11 = 12 x 12 = 144 g

Mass of C in 3.42 g of C12H22O11 = 1.44 g

Mass of H in 342 g C12H22O11 = 22 x 1 = 22 g

Mass of H in 3.42 g of C12H22O11 = 0.22 g

Mass of O in 342 g C12H22O11 = 11 x 16 = 176 g

Mass of O in 3.42 g of C12H22O11 = 1.76 g

Number of atoms = number of moles x 6.023 x 1023 atoms

Number of C atoms=

Number of H atoms=

Number of O atoms=

 

 

  • 74

 moles=3.42/342=1/10

for C, 

in 1 mole of sugar, C=144g

i.e 342---->144g

i.e 3.42--->144/342*3.42=14.4g

moles of C=14.4/12=1.2 moles

atoms= 1.2*Na*12

like wise for each element

  • -13

moles=3.42/342=1/10

for C,

in 1 mole of sugar, C=144g

i.e 342---->144g

i.e 3.42--->144/342*3.42=14.4g

moles of C=14.4/12=1.2 moles

atoms= 1.2*Na*12

like wise for each element

 i hope u like that

  • -25
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