Find the number of integers greater than 7000 that can be formed with the digits 3, 5, 7, 8 and - Maths - Binomial Theorem

Question

Find the number of integers greater than 7000 that can be formed
with the digits 3, 5, 7, 8 and 9 where digits are not repeated

Neha Sethi · Accepted Answer

Dear student
The integers greater  than 7000 formed by  the digits 3,5,7,8,9 (no digits repeated)are of the type (7/8/9)××× or all five digit  integers
The integers of the type (7/8/9)××× are  3×4×3×2=72The five digit  integers formed  by 3,5,7,8,9 (no digits repeated) are 5!=120∴Total number of required integers=72+120=192
Regards

Find the number of integers greater than 7000 that can be formed with the digits 3, 5, 7, 8 and 9 where digits are not repeated.