find the number of ways of arranging 6 players to throw the cricket ball so that the oldest player may not throw first.

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Please find below the solution to the asked query:

$$\begin{gathered} \mathrm{For} \mathrm{first} \mathrm{throw} \mathrm{we} \mathrm{have} 5 \mathrm{options} \left(\mathrm{As} \mathrm{older} \mathrm{player} \mathrm{must} \mathrm{not} \mathrm{throw}\right) \\ \mathrm{For} \mathrm{second} \mathrm{throw} \mathrm{we} \mathrm{have} 5 \mathrm{options} \left(\mathrm{As} \mathrm{one} \mathrm{player} \mathrm{has} \mathrm{already} \mathrm{thrown}\right) \\ \mathrm{For} \mathrm{third} \mathrm{throw} \mathrm{we} \mathrm{have} 4 \mathrm{options} \mathrm{and} \mathrm{so} \mathrm{on}.... \\ \mathrm{Hence} \mathrm{number} \mathrm{of} \mathrm{ways}=5\times 5\times 4\times 3\times 2\times 1=600 \left(\mathrm{Answer}\right) \end{gathered}$$

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