Find the number of ways of distributing 5 Monacco biscuits and 10 brittania biscuits among 5 beggars if each beggar can take any number of biscuits.

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Please find below the solution to the asked query:

Total ways=Number of ways to distribute Monacco×Number of ways to distribute BritaniaWe know that:Number of integral solutions of:x1+x2+....+xr=n where 0x1,x2,...,xrn is equal to n+r-1Cr-1Let beggers be b1,b2,...,b5.For Monnaco, we have:b1+b2+b3+b4+b5=5Number of ways to distribute Monnaco=5+5-1C5-1=9C4For  Britania, we have:b1+b2+b3+b4+b5=10Number of ways to distribute Britania=10+5-1C5-1=14C4Total ways=9C4×14C4 Answer

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  • 53
1 monaco and 2 britannia each 
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