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find the perimeter of shaded region if ABCD is a square of side 14 cm and APBand CPDare semicircles.

 perimeter of the shaded region=circumference of the the two semi-circles+DA+BC
DA=BC=14cm
Cicumference of the two semicircles is equal to that of one circle.
Here,diameter of the circle=14cm
so it's radius=7cm
 
2πr+14+14=
2×22/7×7+14+14=
72cm
so, perimeter of the shaded region=72cm
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hey rajpranav yu r wrong...!
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totally wrong answer u have given
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find the perimeter of the shaded region if abcd is a square of side 21 cm and apb & cpb are semicircles.​
 
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like if u love mia khalifa
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108cm
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Perimeter of shaded region = 2 * side of square + 2 * perimeter of semicircle
                                           = 2 * 14 cm + 2 * 22/7 * 14/2 cm
                                          = 28 + 44 cm = 72 cm
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area of the shaded reason is =  AD + BC + DPC + APB 
                                             =  14 + 14 + pi*r2
                                                            =   28  +  22*7*7
                                                                              7    
                                                            =   182 cm2
                 
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i m so sorry the ans is wrong 
it will be 14+14+2 pi*r
                28+44
               72 cm
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72cm
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all answers are wrong please check agarwal text pg 6.58 for answer
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PERIMETER OF THE SHADED REGION = circumference of the semicircles + 2 x side of the square
                                                                 = 2 pi r  + 2 * 14
                                                                 = 2 *22/7* 7 + 28
                                                                 = 44 + 28 
                                                                  = 72 cm (ans)
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