Find the perimeter of the following. 1. A rectangle whose length 8cm and a diagonal 10cm. 2. A rhombus having diagonals 20cm and 48cm. Share with your friends Share 1 Varun.Rawat answered this (1). Let ABCD be the rectangle in which AC is one of the diagonal.Now, AB = 8 cm and AC = 10 cmWe know that each angle of a rectangle is a right angle.So, ∠A = ∠B = ∠C = ∠D = 90°In ∆ABC, AC2 = AB2 + BC2 Pythagoras theorem⇒102 = 82 + BC2⇒BC2 = 100 - 64⇒BC2 = 36⇒BC = 6 cmNow, perimeter = 2length + breadth=2AB + BC=28 + 6=2×14=28 cm (2). Let ABCD be the rhombus in which diagonals AC and BD intersect at O.Let AC = 48 cm and BD = 20 cmWe know that diagonals of rhombus bisect each other at 90°.So, OA = OC = AC2 = 24 cm and OB = OD = BD2 = 10 cmand ∠AOB = ∠BOC = ∠COD = ∠DOA = 90°In ∆AOB, AB2 = OA2 + OB2 Pythagoras theorem⇒AB2 = 242 + 102⇒AB2 = 576 + 100⇒AB2 = 676⇒AB = 26 cmNow, Perimeter of rhombus = 4 × length of each side of rhombus=4AB=4×26=104 cm 0 View Full Answer Zeba Israr answered this Please answer as fast as you can 2 Vishnu Sai P answered this trbbs -2