find the point on the curve y=2x^2-6x-4 at which the tangent is parallel to x-axis . find tangent equation

Dear Student



y=2x2-6x-4dydx=4x-6For tangent parallel to x-axis, its slope is zero4x-6=0x=64=32We put it in y,y=294-632-4y=92-9-4=-172So, point is 32,-172For equation, it is of the formy-y1=m(x-x1)where, (x1,y1)=32,-172 and m=0y--172=0y=172 is the equation of tangent.

Regards!

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