find the point on the curve y = x2 - 2x =3 where the tangent is parallel to x axis Share with your friends Share 0 Manbar Singh answered this The equation of the given curve is,y = x2 - 2x + 3Let the required point is Px1, y1.Since, the tangent to the curve at Px1, y1 is parallel to x-axis, thendydxx1, y1 = 0Now, y = x2 - 2x + 3⇒dydx = 2x - 2⇒dydxx1, y1 = 2x1 - 2Now, dydxx1, y1 = 0⇒2x1 - 2 = 0⇒x1 = 1Since, Px1, y1 lies on the given curve, so we have y1 = x12 - 2x1 + 3⇒y1 = 12 - 2 × 1 + 3 = 2So, required point is 1, 2 6 View Full Answer Raghav answered this y = x2-2x+3If tangent is parallel to y-axis, then dy/dx = 0 So, dy/dx = 2x-2 = 0 So, x = 1 Putting the value of x in y equation, we get , y = 1-2+3 = 2Hence, at (1,2), the tangent is parallel to y-axis for the given curve. 2 Dishank Gupta answered this (0,2) -1 Dishank Gupta answered this Sorry (1,2) 1
