Find the point on the curve y = x2 2x + 3, where the tangent is parallel to - Maths -

Question

Find the point on the curve y = x 2
− 2x + 3, where the tangent is parallel to
x-axis

Global Expert · Accepted Answer

The slope of the x-axis is 0
Now, let (x1, y1) be the
required point
Here,
Since, the point lies on the curve
Hence, y1=x12-2x1+3            
 1Now, y=x2-2x+3dydx=2x-2Slope of the tangent at x, y=dydxx1, y1=2x1-2Given:Slope of the tangent at x1, y1=Slope of the x-axis=2x1-2=0⇒x1=1andy1=1-2+3=2         [From (1)]∴Required point=x1, y1=1, 2

Find the point on the curve y = x 2 − 2x + 3, where the tangent is parallel to x-axis.

Find the point on the curve y = x ² − 2x + 3, where the tangent is parallel to x-axis.