Find the point on x axis which is equidistant from the point (7,6) and (-3,4) Share with your friends Share 0 Padhmapriya Nagarajan answered this Dear Student,Distance formula :x-x12 + y-y12Let (x,y) be the point we need to find out, but as the point lies on x axis y=0Thus the point is of the form (x,0)Substituting values,x-72 + 62=x+32 + 42Squaring of both sides and solving the equation to find x:x2+49-14x +36= x2+16+9+6x20x = 60x=3We get the point (x,y) as (3,0)Regards. 5 View Full Answer Nazeer Mohammed answered this (3,0) is the point which is equidistant from point (7,6) and (-3,4) -2
