Find the point on x-axis which is equidistant from the points (2,-5) and (-2,9)
Let the point on x-axis is P(x, 0), which is equidistant from the points (2,-5) and (-2, 9)
We know the distance formula between two points is,
…… (1)
So, distance between the point P(x, 0) and A (2,-5) is,
And the distance between the point P(x, 0) and B (-2, 9) is,
Since (x, 0) is equidistant from the other two point.
So,
Squaring on both sides, we have
Hence required point is (-7, 0).