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Find the point on Y-axis which is equidistant from the points (5,-2) and (-3,2)?

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Hi,

Since the point is on y-axis it's coordinates are (0,y).

If P(0,y) be the point equidistant from A(5,-2) and B(-3,2),

AP=BP  Given

AP^2=BP^2  squaring as to remove roots.

(0-5)^2+(y+2)^2=

(-3-0)^2+(2-y)^2

=25+y^2+4y+4=9+4-4y+y^2

=16= -8y

So,y= -2.

  • 51

 Take the point P(0,y) since it is on y-axis now since it is given equidistant so we can apply the following formula

-2+2/2 = y 

0=y 

therefore we are seeing that the required point is P(0,0) which is the origin!!

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 Sorry bro my previous post is wrong i thought the point is on the line ....

Since the point is on y-axis it 's coordinates are (0,y).

If P(0,y) be the point equidistant from A(5,-2) and B(-3,2),

AP=BP Given

AP^2=BP^2 squaring as to remove roots.

(5-0)^2+(y+2)^2=

(0-3)^2+(2-y)^2

=25+y^2+4y+4=9+4-4y+y^2

=16= -8y

So,y= -2.

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