find the points of discontinuity of the function 'f' given by

f(x)={ |x|+3, x less than or equal to -3;

-2x, x greater than -3 and less than 3;

6x+2, x greater than 3;

Anwer needed ASAP...!!

f(x)  = |x|+3 , x-3-2x ,-3<x<3             6x +2 ,x3When x -3 , thenlimx-3- |x| +3 = 0And when x > -3 , limx-3+ -2x  = 6 And value of f(x) at x =-3 is  0 Hence the limits are not equalHence at x =-3 the function is discontinuos.When x <3 limx3- -2x = -6 When x >3limx3+6x +2 = 20And the value of function is 6x +2 = 20 at x = 3Hence Hence the limits are not equalHence at x =3 the function is discontinuos

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