find the points on the curve y=x3-7x+3 at which the equation of the tangent is y=x-11 - Maths - Application of Derivatives

Question

find the points on the curve y=x3-7x+3 at which the
equation of the tangent is y=x-11

Sanat K Mukherjee · Accepted Answer

Dear Student,
Given,y=x3-7x+3Tangent at the point (x,y)dydx=3x2-7Given, the equation of the tangent is y=x-11Slope of the tangent = 1So, 3x2-7=13x2=8x=±83=±263For, x=263=1
63, y=x-11y=263-11=26-333=4 9-333=-28 13=-9
37For, x=-263, y=x-11y=-263-11=-4 9-333=-37 93=-12
6So, the points may be(1 63, -9
37) or (-1 63, -12 6)

Regards

find the points on the curve y=x3-7x+3 at which the equation of the tangent is y=x-11.

find the points on the curve y=x³-7x+3 at which the equation of the tangent is y=x-11.