Find the probability that in a random arrangement of the letters of the word "INSTITUTION" the three T's are together.

Given word: INSTITUTION

Total letters = 11

The word contains 3 I, 2 N, 1 S, 3 T, 1 U and 1 O

Total number of arrangement = 11!/(3!*2!*3!) = 554400

Now, taken 3 T are together.

So total latter = 9

The number of favorable cases = 9!/(3!*2!) = 30240

Now, P(3 T are togather) = 30240/554400 = 0.0545

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