# Find the ratio in which the line 3x + y - 9 = 0 divides the line segment joining the points A(1,3) and B(2,7)

Let be line 3x + y – 9 = 0 divides the line segment joining the pints A (1, 3) and B (2, 7) in the ratio k: 1 at point C. Thus, the line 3x + y – 9 = 0 divides the segment joining A (1, 3) and B (2, 7) in the ratio 3:4.

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thanks

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thanks

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why is the ratio taken as k:1?
plzzz answer
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suppose the line 3x+y-9=0 divides the line sebment joining A(1,3) and B(2,7) in the ratio k:1 at point C. then the coordinates of C are
{2k+1 7k+3}
k+1      k+1
but, C lies on 3x+y-9=0. therefore
3{2k+1 }+ 7k+3    -9=0 => 6k+3+7k+3-9k-9=0 => k=3/4
k+1         k+1

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x=(2-1)(2-1)

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thank u so much
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See • -16
Thanks
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Plz thumb my answer • 60
THANKS UTKARSH
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Let be line 3x + y – 9 = 0 divides the line segment joining the pints A (1, 3) and B (2, 7) in the ratio k: 1 at point C. Thus, the line 3x + y – 9 = 0 divides the segment joining A (1, 3) and B (2, 7) in the ratio 3:4.
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Thanks
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I hope this answer is right • -2
Yo • 14
Answer is given below:- • 1
find the points A(x,y)B(3,6)C(-3,4) are collinear show that x-3y+15=0
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K =3:4
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https://youtu.be/oEq4G_n7Dxg
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determine the ratio in which the line 3x+y-9=0 divides the segment joining the points (1,3) and (2,7)

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