find the real value of x and y (1+I)y2+(6+i)=(2+i)x Share with your friends Share 1 Tanveer Sofi answered this We have1+iy2+6+i=2+ix⇒y2+6+y2+1i=2x+ixEquating the real and imaginary parts, we gety2+6=2x ....... 1 and y2+1=x ........2Substituting y2=x-1 from the equation 2 into the equation 1, we getx-1+6=2x⇒x+5=2x⇒x=5 Subtracting x from both sidesPutting x=5 in the 2, we havey2=5-1=4⇒y=±2Hence, the value of x is 5 and the values of y are 2, -2. 0 View Full Answer