Find the roots of the equation 2xsquare+10x+20=0 Share with your friends Share 0 Manbar Singh answered this The given quadratic equation is, 2x2 + 10x + 20 = 0⇒2x2 + 5x + 10 = 0⇒x2 + 5x + 10 = 0Now, a = 1; b = 5; c = 10Now, D = b2 - 4ac = 52 - 4110 = 25 - 40 = -15<0So, the above equation has imaginary roots. x = -b + D2a and x = -b - D2a⇒x = -5 + -152 and x = -5 - -152⇒x = -5 + 15i2 and x = -5 - 15i2 as, i2 = -1 3 View Full Answer
