find the separate equation ofx2+2(cosec α)xy+y2=0 Share with your friends Share 6 Ajanta Trivedi answered this the given homogeneous equation of 2 degree is x2+2.cosecα.xy+y2=0 ...........(1) x2+[(cosecα+cotα)+(cosecα-cotα)]xy+y2=0x2+(cosecα+cotα).xy+(cosecα-cotα)xy+y2=0x.[x+(cosecα+cotα)y]+y.(cosecα-cotα).[x+ycosecα-cotα]=0x.[x+(cosecα+cotα)y]+y.(cosecα-cotα).x+y.(cosecα+cotα=0 [since 1cosecα-cotα=1cosecα-cotα*cosecα+cotαcosecα+cotα=cosecα+cotαcosec2α-cot2α⇒[x+y.(cosecα+cotα)][x+y.(cosecα-cotα]=0⇒x+y.(cosecα+cotα)=0 or x+y.(cosecα-cotα)=0 hope this helps you -1 View Full Answer