find the solutions of x +y = 6 and 2x + 3y = 8

Dear Student,


 x +y = 6           (I)2x + 3y = 8         (II)Applying (II)-2×(I)2x+3y-2x+y=8-2×62x+3y-2x-2y=8-12y=-4Put in (I)x-4=6x=4+6x=10

Regards

  • -1
y = 4; x= 2
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x+y=6 => 2x +2y = 12
2x +3y = 8

subtract the eqns

y= -4
x= 10
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