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Find the square root of 10+√( 24)+√( 60)+√40

$\sqrt{10 + \sqrt{24} + \sqrt{60} + \sqrt{40}} = \sqrt{2 + 3 + 5 + 2 \sqrt{6} + 2 \sqrt{15} + 2 \sqrt{10}} = \sqrt{(\sqrt{2})^{2} + (\sqrt{3})^{2} + (\sqrt{5})^{2} + 2 \sqrt{2} \sqrt{3} + 2 \sqrt{3} \sqrt{5} + 2 \sqrt{5} \sqrt{2}} = \sqrt{(\sqrt{2} + \sqrt{3} + \sqrt{5})^{2}} = \sqrt{2} + \sqrt{3} + \sqrt{5}$

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