Find the square root of this complex number:

2+3i/5-4i + 2-3i/5+4i

Dear student,

Kindly find the answer to your query:
2+3i5-4i+2-3i5+4i= 10+8i+15i-12+10-15i-8i+1225+16=2041So square root of 2+3i5-4i+2-3i5+4i=2041=0.698

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  • 0
Simplifying them yields the result 
{( 2 + 3 i  ) ( 5 + 4 i ) + ( 2 - 3 i ) ( 5 - 4 i ) }  / ( 5 2 + 4 2 )
=> ( 2 + 33 i - 2 - 33 i ) / 41 
=> 0 / 41 = 0 
Square root of zero is zero itself 
  • -19
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