FIND THE SUM OF 1/2 + 1/6 + 1/12+ 1/20 + 1/30 + 1/42 + 1/56 + 1/72 + 1/90 + 1/110 + 1/132A) 7/8B) 11/12C) 15/16D) 17/18

1/2 + 1/6 + 1/12 + 1/20 + 1/30 + 1/42 + 1/56 + 1/72 + 1/90 + 1/110 + 1/132

= (1 - 1/2) + (1/2 - 1/3) + (1/3 - 1/4) + (1/4 - 1/5) + (1/5 - 1/6) + (1/6 - 1/7) + (1/7 - 1/8) + (1/8 - 1/9) + (1/9 - 1/10) + (1/10 - 1/11) + (1/11 - 1/12)

= 1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + 1/4 - 1/5 + 1/5 - 1/6 + 1/6 - 1/7 + 1/7 - 1/8 + 1/8 - 1/9 + 1/9 - 1/10 + 1/10 - 1/11 + 1/11 - 1/12

= 1 - 1/12

= 12/12 - 1/12

= 11/12

• -1

1/2 + 1/6 + 1/12 + 1/20 + 1/30 + 1/42 + 1/56 + 1/72 + 1/90 + 1/110 + 1/132

= (1 - 1/2) + (1/2 - 1/3) + (1/3 - 1/4) + (1/4 - 1/5) + (1/5 - 1/6) + (1/6 - 1/7) + (1/7 - 1/8) + (1/8 - 1/9) + (1/9 - 1/10) + (1/10 - 1/11) + (1/11 - 1/12)

= 1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + 1/4 - 1/5 + 1/5 - 1/6 + 1/6 - 1/7 + 1/7 - 1/8 + 1/8 - 1/9 + 1/9 - 1/10 + 1/10 - 1/11 + 1/11 - 1/12

= 1 - 1/12

= 12/12 - 1/12

= 11/12

therefore the answer is option B)11/12

• 4

11/12

• 3
Un conjunto de n numeros, suman un valorS. Sicada número del conjunto se aumenta 20 unidades, después se multiplica por 5 y posteriormente se disminuyeen 20 unidadesCuálseráel valorde la sumade losnúmerosdespuésde estas operacionesanteriores?
• -1
= 11/12
• 4
ans=11/12

• 2
yes 11/12

• 0
11
2
• -1
11/12

• 4
B)11/12
• 1
11/12
• 0
11
12
• 0
11/12
• 0
11/12

• 1
• 0
11/12
• 0
1/2 + 1/6 + 1/12 + 1/20 + 1/30 + 1/42 + 1/56 + 1/72 + 1/90 + 1/110 + 1/132

= (1 - 1/2) + (1/2 - 1/3) + (1/3 - 1/4) + (1/4 - 1/5) + (1/5 - 1/6) + (1/6 - 1/7) + (1/7 - 1/8) + (1/8 - 1/9) + (1/9 - 1/10) + (1/10 - 1/11) + (1/11 - 1/12)

= 1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + 1/4 - 1/5 + 1/5 - 1/6 + 1/6 - 1/7 + 1/7 - 1/8 + 1/8 - 1/9 + 1/9 - 1/10 + 1/10 - 1/11 + 1/11 - 1/12

= 1 - 1/12

= 12/12 - 1/12

= 11/12

therefore the answer is option B)11/12
• 0
Yup that is 11/12
• 1
very easy question and very easy answer of this
• -1
11/12
• 0

• 0
-1\2 between 2/4
• 0
Ans is B
• 0

• 1
11/12
• 0
11/12
• 0
11/12
• 0
good
• 0
Highest common factor
• 0
Hi how are you
• 0
which two teams are between 66
• 0
Don't know
• 0
08427896
• 0
The answer is 0.91666667 or B
• 0
Desending
• 0

• 0
Ui9i
• 0
prove that 3 upon 5 is a rational number
• 0
simplify in relational number minus 8 by 15 + 2 by -3
• 0
847/924
• 0
9and5
• 0
First take a LCM of denaminat number next add it
• 0
oneplus 2 3
• 0
To tough
• 0
• 1

1/2 + 1/6 + 1/12 + 1/20 + 1/30 + 1/42 + 1/56 + 1/72 + 1/90 + 1/110 + 1/132

= (1 - 1/2) + (1/2 - 1/3) + (1/3 - 1/4) + (1/4 - 1/5) + (1/5 - 1/6) + (1/6 - 1/7) + (1/7 - 1/8) + (1/8 - 1/9) + (1/9 - 1/10) + (1/10 - 1/11) + (1/11 - 1/12)

= 1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + 1/4 - 1/5 + 1/5 - 1/6 + 1/6 - 1/7 + 1/7 - 1/8 + 1/8 - 1/9 + 1/9 - 1/10 + 1/10 - 1/11 + 1/11 - 1/12

= 1 - 1/12

= 12/12 - 1/12

= 11/12

• 0
11/12
• 0
B)11/12
• 0
ans is b

• 0
The rational number is in the p/q form where q is not equal to 0
• 0
11/12 is the correct option
• 0
What is this
• 0
1/2-4/8-9/5
• 0
Irshas Mohd.

• 0
Hey brother11/2
• 0
=11/12
• 0
1/2 + 1/6 + 1/12 + 1/20 + 1/30 + 1/42 + 1/56 + 1/72 + 1/90 + 1/110 + 1/132

= (1 - 1/2) + (1/2 - 1/3) + (1/3 - 1/4) + (1/4 - 1/5) + (1/5 - 1/6) + (1/6 - 1/7) + (1/7 - 1/8) + (1/8 - 1/9) + (1/9 - 1/10) + (1/10 - 1/11) + (1/11 - 1/12)

= 1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + 1/4 - 1/5 + 1/5 - 1/6 + 1/6 - 1/7 + 1/7 - 1/8 + 1/8 - 1/9 + 1/9 - 1/10 + 1/10 - 1/11 + 1/11 - 1/12

= 1 - 1/12

= 12/12 - 1/12

= 11/12

therefore the answer is option B)11/12
• 0

1/2 + 1/6 + 1/12 + 1/20 + 1/30 + 1/42 + 1/56 + 1/72 + 1/90 + 1/110 + 1/132

= (1 - 1/2) + (1/2 - 1/3) + (1/3 - 1/4) + (1/4 - 1/5) + (1/5 - 1/6) + (1/6 - 1/7) + (1/7 - 1/8) + (1/8 - 1/9) + (1/9 - 1/10) + (1/10 - 1/11) + (1/11 - 1/12)

= 1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + 1/4 - 1/5 + 1/5 - 1/6 + 1/6 - 1/7 + 1/7 - 1/8 + 1/8 - 1/9 + 1/9 - 1/10 + 1/10 - 1/11 + 1/11 - 1/12

= 1 - 1/12

= 12/12 - 1/12

= 11/12

• 1
A fraction is a number representing a part of a whole while a?rational number?is any?number?that can be expressed as the?quotient?or fraction?p/q?of two?integers, with the?denominator?q?not equal to zero
• 0
:) nice
• 0
Nahi pata yaar
• 0
11/12
• 0
I don't know answer this question
• 0
What are you looking for?