find the sum of 24 terms whose nth term is 3+2n/3 answer

a_n= 3+ 2n / 3 {given}

then if n=1 then

a₁=3 + 2(1)/3

a=11/3

similarly...

if n=2 then

a₂=3 + 2(2) / 3

a₂=13/3

we know that s_n== n/2[ 2a + (n-1)d]

s₂₄₌12 [22/3 +(23)2/3]

= 12 [ 68/3]

= 272

therefour, the sum of 24 terms is 272...

hope this is right...:D