find the sum of all natural numbers between 250 and 1000 which are exacty divisible by 9

## CERTIFIED ANSWER

a=252 (as it is next number divisible by 9)

d=9

l=999 (as last number divisible by 9)

to find n

999=252+(n-1)9

747=9n-9

756=9n

n=84

S84 =

84/2(252+999)= 52542

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