find the sum of all natural numbers between 250 and 1000 which are exacty divisible by 9
a=252 (as it is next number divisible by 9)
d=9
l=999 (as last number divisible by 9)
to find n
999=252+(n-1)9
747=9n-9
756=9n
n=84
S84 =
84/2(252+999)= 52542
find the sum of all natural numbers between 250 and 1000 which are exacty divisible by 9
a=252 (as it is next number divisible by 9)
d=9
l=999 (as last number divisible by 9)
to find n
999=252+(n-1)9
747=9n-9
756=9n
n=84
S84 =
84/2(252+999)= 52542