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Find the sum of first five multiples of 3?

First five multiple of 3 are:

3, 6, 9, 12, 15

Here first term, a = 3

common difference, d = 6 – 3 = 3

Number of term, n = 5

⇒ s5 = 9 × 5 = 45

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s5=52[3+15]

S5=52(18)

S5=45

  • 3

 S5 =  5 2 ( 2*5 + ( 5 - 1 ) 5

  = 52 ( 30 )

 = 75 :))

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* itz 5  divided by 2 in de first nd as well as 2nd step !! :)  nt 52 !! :(

  • 0

first 5 multiples are 3, 6,9 ......

a=3

d=3

n=5

Sn= n/2 [2a+(n-1)d]

so putting in all d values we get the answer to be 45.... hp it helps. thumbs up plzzzz

  • 1

 oopz srry i thought it z first  3 multiples of 5 !! .............. hitha nd unbeatable guy R ri8 !! :))

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