find the sum of the first 30 positive integers divisibleby 6.

  • 1
a = 6
l = 180
n = 30


s
n =    n(a+l)/2
    =  30(6+180)/2 
    =  30*180/2
    =   2700

therefore sum of first 30 positive integers divisible by 6 is 2700
 
  • 3
a= 6
d=6
n=30

S= 30/2 [2(6)+29(6)]
  =15 (12+ 174)
  =15(186)
  =2790
 
  • 10
2700
  • 0
What are you looking for?