Find the sum to n terms of the series 1x3x5+3x5x7+5x7x9+....

Sum upto nth term1×3×5 + 3×5×7+5×7×9.... n termsSo the nth term of this expression is n(n+2)(n+4) , here n is natural numberSo  n(n+2)(n+4)=n3+6n2+8nAnd n=1n=nn3=[n(n+1)]24, n=1n=nn2=n(n+1)(2n+1)6, n=1n=nn=n(n+1)2So n=1n=n(n3+6n2+8n)=[n(n+1)]24+6×[n(n+1)(2n+1)6]+8×n(n+1)2So on solving we get =n(n+1)[n(n+1)4+(2n+1) +4] (Ans)

  • -5

i think u can solve it by the formula ---- (n)(n+2)(n+4)

  • 5
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