find the tem independent of x in (2x^2-1x)^12

Let (r + 1) term is independent of x
So (2x²- x)¹²
So by binomial expansion we have
T_r+1 = ¹²C_r (2x²)^12-r (-x)^r
= ¹²C_r 2^12-r x^24-2r (-x)^r
= ¹²C_r 2^12-r (x)^24-2r  (-1) ^r (x)^r
= ¹²C_r 2^12-r (-1) ^r (x) ^24-r
For this expression to be independent of x, 24 -r should be equal to zero.
So r =24, that is not possible as n is greater tha equal to r.
So in this expression there is no term independent of x.