Find the term independent of x in the expansion of [2x2+1/x]12

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We have 2x2+1x12Let r+1th term be independent of x.Tr+1=12Cr 2x2r1x12-r=12Cr.2r.x2r.1x12-r=12Cr.2r.x2r-12+r=12Cr.2r.x3r-12As above term is independent of x, hence,3r-12=0r=4Hence r+1=5th term is independent of x.T4+1=12C4.24 T5=16.12C4 Answer

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