Find the term independent of x in the expansion of {x+ 1/x}12
Tr+1= 12Cr(x)12-r(1/x)r
= 12Cr(x)12-r(x)-r
= 12Cr(x)12-2r
12 -2r = 0
12 = 2r
r = 6
T6+1 = T7
T7 is independent of x.
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Best of Luck!
Find the term independent of x in the expansion of {x+ 1/x}12
Tr+1= 12Cr(x)12-r(1/x)r
= 12Cr(x)12-r(x)-r
= 12Cr(x)12-2r
12 -2r = 0
12 = 2r
r = 6
T6+1 = T7
T7 is independent of x.
Cheers!!
Best of Luck!