Find the term independent of x in the expansion of {x+ 1/x}12

Tr+1= 12Cr(x)12-r(1/x)r

= 12Cr(x)12-r(x)-r

= 12Cr(x)12-2r

12 -2r = 0

12 = 2r

r = 6

T6+1 = T7

T7 is independent of x.

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