find the value of (10-5)1/2 using log

Let,

y=(10-5)1/2

Taking log on both sides,

log y=log (10-5)1/2

log y=1/2 log(10-5) [We know log ay=y log a]

log y=1/2 log(1/105)

log y=1/2 [log1-log 105] [we know log(a/b)=log a-log b]

logy=1/2 [0-log105] [log1=0]

logy=1/2 [-log105]

logy=1/2 [-5 log10] [We know log ay=y log a]

logy=-5/2 log10

  • 1
What are you looking for?