find the value of (10-5)1/2using log table
Let y=(10-5)1/2
Taking log on both sides, we get,
log y=log (10-5)1/2
log y=1/2 log(10-5) [ log ay=y log a]
log y=1/2 log(1/105)
log y=1/2 [log1-log 105] [ log(a/b)=log a-log b]
logy=1/2 [0-log105] [log1=0]
logy=1/2 [-log105]
logy=1/2 [-5 log10] [ log ay=y log a]
logy=-5/2 log10