Find the value of a for which the function f(x)= x square -2ax+6,,x>0 is strictly increasing . Please don't give links Share with your friends Share 5 Varun Rawat answered this We have,fx = x2 - 2ax + 6f'x = 2x - 2a = 2x - aSince, fx is strictly increasing when x > 0, then f'x >0So, 2x - a > 0⇒x > aSo, a≤0 as, x >0 3 View Full Answer
