find the value of 'a' for which the lines x=1 y=2 and ax+2y-6=0 are concurrent... no links plzz

Dear Student,

​Since the given lines are concurrent, they all pass through a single point. The given lines are:
x = 1                   ...(i)
y = 2                   ...(ii)
ax + 2y - 6 = 0    ...(iii)

Since they pass through a common point, this point must be (1,2), which is the point of intersection of the lines x = 1 and y = 2. Substituting x = 1 and y = 2 in equation (iii), we get:
a(1) + 2(2) - 6 = 0 or a = 6 - 4 = 2

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ax + 2y = 0 a.1 + 2.2 = 0 1a + 4 = 0 a = -4 (here [.] represent for into) THANK U.
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