Find the value of tan 1/3(tan inverse x + tan inverse 1/x). Please help me as quick as possible. Share with your friends Share 0 Devesh Kumar answered this we have tan13tan-1x+tan-11xUsing tan-1x+tan-1y=tan-1x+y1-xytan13tan-1x+tan-11x=tan13tan-1x+1x1-x×1x=tan13tan-1∞ As tan-1=π2=tanπ2×3=tanπ6=13 Answer 0 View Full Answer Anurag answered this answer=1/3^1/2 1
